Respuesta :

rdacoder

[tex]Factor\ by\ grouping:\\\\2x^2+3x-35\\\\(2x-7)(x+5)\\\\2x-7=0\ and\ x+5=0\\\large\boxed{\therefore x=\frac{2}{7}\ and\ x=-5}[/tex]

Answer:  2x^2+3x-35=(x+5)(2x-7)

Step-by-step explanation:

[tex]2x^2+3x-35=\\2x^2+10x-7x-35=\\(2x)(x+5)-(7)(x+5)=\\(x+5)(2x-7)[/tex]