beckymyers2001
beckymyers2001 beckymyers2001
  • 11-02-2017
  • Mathematics
contestada

(m^3p^5divide by n^7)x(m^2n^0p^3divdie bye m^4n^2)^3

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apologiabiology
apologiabiology apologiabiology
  • 12-02-2017
convert division to exponent neative
also, n^0=1 so get rid of that nonesense
also we have m^2/m^4 so we are left wiht 1/(m^2) or m^-2

so
[tex](m^3p^5n^{-7})(p^3m^{-2}n^{-2})^3[/tex]=
[tex](m^3p^5n^{-7})((p^3)^3)((m^{-2})^3)((n^{-2})^3)[/tex]=
[tex](m^3p^5n^{-7})(p^9)(m^{-6})(n^{-6})[/tex]=
[tex](m^3)(p^5)(n^{-7})(p^9)(m^{-6})(n^{-6})[/tex]=
[tex](m^{-3})(p^{14})(n^{-13})[/tex]=
[tex] \frac{p^{14}}{m^3n^{13}} [/tex]
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