highflylex6511
highflylex6511
11-10-2022
Mathematics
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moneyromo11734
moneyromo11734
11-10-2022
[tex]27)\frac{4x^0y^{-2}z^3^{}^{}}{4x}=x^{0-1}y^{-2}z^3=x^{-1}y^{-2}z^3=\frac{z^3}{xy^2}[/tex][tex]undefined[/tex]
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