Jackson00000
Jackson00000 Jackson00000
  • 10-06-2017
  • Mathematics
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Plz help..............refresh the page before u answer

Plz helprefresh the page before u answer class=

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irspow
irspow irspow
  • 10-06-2017
If you factor the denominator of the left multiplicand...

[(a-4)(a+3)]/[a(a-4)]  you can see that the (a-4)s cancel out leaving:

(a+3)/a

now you have

(a+3)/a * 2a^3/((a+3)(a-1))  so the (a+3)s cancel out leaving:

1/a * 2a^3/(a-1)  which is:

2a^3/(a(a-1))  so now a^1 cancel leaving

2a^2/(a-1)
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