crynicole87ow6v4p crynicole87ow6v4p
  • 13-09-2017
  • Mathematics
contestada

how do you solve
(x-5)^2-4(x-5)-21=0

Respuesta :

carealee
carealee carealee
  • 13-09-2017
Let's solve your equation step by step.

(x-5)^2 -4(x - 5) - 21 = 0

Step 1: Simply both sides of the equation.

x^2 - 14x + 24=0

Step 2: Factor left side of the equation.

(x - 2)(x - 12) = 0

Step 3: Set factors equal to 0.

x - 2 = 0 or x - 12 = 0

x = 2 or x = 12

Answer: 

x = 2 or x = 12


Answer Link

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