a rectangular garden has a perimeter of 54 feet. it's length is 3 less than twice its width. write and solve an equation to solve for the gardens dimensions
2(L+W)=54 L=2W-3 Substitute L in the first equation: 2((2W-3)+W)=54. Divide by 2: (2W-3)+W=27 Simplify by collecting like terms: 3W-3=27. Add 3: 3W=30. Divide by 3 to get that W=10. Substitute the L and W relations to get L=2W-3 L=2*10-3 L=17. The answers are length is 17 and width is 10.