A normal human heart, beating about once per second, creates a maximum 4.00-mv potential across 0.250 m of a person\'s chest, producing a 1.00-hz electromagnetic wave. what is the maximum electric field strength produced?

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calculista calculista · Answer 1 · 2018-04-20T06:36:24+02:00

If we have a 4mV potential accross 0.250 m

We apply

E = V/m

E = 4mV/0.25m = 0.016 V/m (Max Electric field)

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shirleywashington shirleywashington · Answer 2 · 2019-03-25T06:53:59+01:00

Explanation :

It is given that,

Potential, [tex]V=4\ mV=4\times 10^{-3}\ V[/tex]

This potential across the person's chest is at a distance of 0.250 m

Frequency of electromagnetic wave, f = 1 Hz

We know that the electric field is defined as :

[tex]E=\dfrac{V}{d}[/tex]

V is the potential

d is the distance

[tex]E=\dfrac{4\times 10^{-3}\ V}{0.250\ m}[/tex]

[tex]V=0.016\ V/m[/tex]

So, the maximum electric strength is 0.016 V/m.

Hence, this is the required solution.