The first thing you would do is "bring" the 10 over by subtracting 10 from both sides
[tex]3x^2+13x-10=0[/tex]
Now, you would want to factor
[tex](3x-2)(x+5)=0[/tex]
Then, set each factor equal to zero, and solve
3x-2 = 0
3x = 2
x = 2/3
AND
x+5 = 0
x=-5
