brainchildisback128 brainchildisback128
  • 11-05-2020
  • Mathematics
contestada

How many ml of a 30% salt solution must be mixed with a 100 ml of a 10% salt
solution to increase the salt concentration to 18%?

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sqdancefan
sqdancefan sqdancefan
  • 11-05-2020

Answer:

  66 2/3 mL

Step-by-step explanation:

Let v represent the volume in mL of added 30% solution. Then the amount of salt in the mix is ...

  0.10×100 +0.30×v = 0.18(100 +v)

  0.12v = 0.08(100) . . . . .subtract (0.18v +0.10×100)

  v = 8/0.12 . . . . . . . . . . . divide by the coefficient of v

  v = 66 2/3 . . . . mL

Adding 66 2/3 mL of 30% salt solution to 100 mL of 10% salt solution will make 166 2/3 mL of 18% salt solution.

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